Homework, Material, and Software Manual for Math 4610
Routine Name: absVec1Error
Author: Tanner Wheeler
Language: Python. This code can be run on a python 3 compiler. The file can be imported and then the method will run.
Description/Purpose: This will compute the absolute error between two vectors using the l_1 vector norm. This can be run for any size of vector with integer, float, and double values. This method does use the method norm1vec(x, m).
Input: There are three inputs for this method. The first two inputs are the two vectors you want to compare. The third input is the size of both vectors. Both vectors need to be of the same size.
Output: This routine returns a double precision value for the absolute error using the l_1 vector norm.
Usage/Example:
First let’s create two vectors c and d of size 3 and set each element to a specific number.
m = 3
c = [float(0) for i in range(0, m)]
d = [float(0) for i in range(0, m)]
c[0] = 1.5
c[1] = 9.4
c[2] = 3.3
d[0] = 1
d[1] = 9
d[2] = 3
Now let’s print out the value returned from our function given our vectors and their size.
print(absVec1Error(c, d, m))
This will print
1.2000000000000002
to the console.
Implementation/Code: The following is the code for absVec1Error(x, y, m)
def absVec1Error(x, y, m):
z = [float(0) for i in range(0, m)]
for i in range(m):
z[i] = x[i] - y[i]
return norm1vec(z, m)
Last Modified: December 2018